Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.2 - Quadrilaterals - Exercise - Page 391: 1

Answer

$60~cm$, $225 \ cm^2$

Work Step by Step

The perimeter of the square is the sum of the lengths of the four sides, that is $4b=4\cdot 15=60\ cm.$ The area is the square of the length of a side, that is, $b^2=15^2=225\ cm^2$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.