Answer
$$65900 \ in^3, \ 6150\ in^2$$
Work Step by Step
The volume of the frustum cone is given by $$ V = \frac{1}{3}h(B_1 + B_2+ \sqrt{ B_1B_2})= \frac{1}{3}(45)(\pi)(18^2+25^2+\sqrt{18^2\cdot 25^2})=65926.321 \ in^3\approx 65900 \ in^3$$
The lateral surface area is given by $$ A = \pi s (r_1+r_2)= \pi (18+25)\sqrt{45^2+(25-18)^2}=6152.09\ in^3\approx 6150\ in^2$$
Where we used the Pythagorean theorem to find the slant height as follows
$$s=\sqrt{45^2+(25-18)^2}=45.54 \ in$$
