Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Review - Page 445: 33

Answer

a. $$57,300\ m^3 .$$ b. $$6380\ m^2 .$$

Work Step by Step

a. The volume of the cone is given by $$ V=\frac{1}{3} \times base \ area \times altitude = \frac{1}{3} \pi (37.6^2)(38.7)=57294.8\ m^3 \approx 57,300\ m^3 .$$ b. The slant height of the cone is given by $s=\sqrt{38.7^2+37.6^2}=53.96\ m$ The lateral surface area is given by $$ Surface \ area= \pi r s=\pi (37.6) (53.95)=6372.78\ m^2\approx 6380\ m^2 .$$
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