Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Review - Page 444: 25

Answer

$$1.55 \ rad .$$

Work Step by Step

Since the distance that the wheel travels is given by $s=r\theta$, then by substitution and using the fact that the radius is half of the diameter, we have $$ 20= (25.8/2) \times \theta \Longrightarrow 2\times20= 25.8\times \theta \\\Longrightarrow\theta=\frac{2\times 20}{25.8}=1.55 \ rad .$$
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