Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Review - Page 444: 18

Answer

$BC=8 \ m$

Work Step by Step

Since ED and BC are parallel, then we have $\angle B=\angle E$ and $\angle C=\angle D$ and $\angle A$ is the common angle. Hence, the triangle AED is similar to the triangle ABC and hence $$ \frac{AE}{AB}=\frac{ED}{BC} \Longrightarrow \frac{4}{8}=\frac{4}{BC} \Longrightarrow BC=8 \ m .$$
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