Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.5 - Finding Factors of Special Products - Exercise - Page 354: 38

Answer

$9x^2(5x-1)(5x+1)$

Work Step by Step

First, we take a common monomial factor as follows $$ 225x^4-9x^2=9x^2(25x^2-1) .$$ This is a difference between two squares, and hence $$ (25x^2-1)=(5x-1)(5x+1) .$$ One can check as follows $$ 9x^2(5x-1)(5x+1)=9x^2(25x^2-5x+5x-1)=9x^2(25x^2-1)=225x^4-9x^2 .$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.