Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.5 - Finding Factors of Special Products - Exercise - Page 354: 2

Answer

$(b-1)(b-1)$

Work Step by Step

This is a perfect square trinomial, and hence $$b^2-2b+1=(b-1)(b-1).$$ One can check as follows $$b-1)(b-1).=b^2-b-b+1=b^2-2b+1 .$$
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