Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.7 - Addition and Subtraction of Fractions - Exercise - Page 41: 68

Answer

5$\frac{13}{16}$ A

Work Step by Step

Let the five currents are 1$\frac{1}{2}$ A , $\frac{3}{4}$ A ,$\frac{3}{16}$ A,$\frac{7}{8}$ A, and 2$\frac{1}{2}$A total current = 1$\frac{1}{2}$ A+ $\frac{3}{4}$ A + $\frac{3}{16}$ A+$\frac{7}{8}$ A+ 2$\frac{1}{2}$A = $\frac{3}{2}$ + $\frac{3}{4}$ + $\frac{3}{16}$ + $\frac{7}{8}$A + $\frac{5}{2}$A =$\frac{8}{2}\times$ $\frac{8}{8}$ + $ \frac{3}{4} \times$ $\frac{4}{4}$ + $\frac{3}{16}$ +$ \frac{7}{8} \times$ $\frac{2}{2}$ =$\frac{64}{16}$ + $\frac{12}{16}$ `+ $\frac{3}{16}$ + $\frac{14}{16}$ =$\frac{93}{16}$ =5$\frac{13}{16}$ A
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