Answer
3$\frac{1}{4}$ A
Work Step by Step
Let the two currents are 1$\frac{3}{4}$ A and 1$\frac{1}{2}$A
total current = 1$\frac{3}{4}$ + 1$\frac{1}{2}$
= $\frac{7}{4}$ + $\frac{3}{2}$
=$\frac{7}{4}$ + $ \frac{3}{2} \times$ $\frac{2}{2}$
=$\frac{7}{4}$ + $\frac{6}{4}$ `
=$\frac{13}{4}$
=3$\frac{1}{4}$ A
