Answer
142$\frac{23}{24}$ oz
Work Step by Step
Let the weight of the different parts of the product are 3$\frac{1}{2}$ oz, 33$\frac{1}{8}$ oz, 6 lb, 10$\frac{1}{3}$ oz
given 1 lb =16 oz
So 6 lb = 96 oz
total product weight = 3$\frac{1}{2}$ oz + 33$\frac{1}{8}$ oz + 96 oz + 10$\frac{1}{3}$ oz
=$\frac{7}{2}$ + $\frac{265}{8}$ + 96 + $\frac{31}{3}$
= $ \frac{7}{2} \times$ $\frac{12}{12}$ + $ \frac{265}{8} \times$ $\frac{3}{3}$ + 96 $ \times$ $\frac{24}{24}$ + $ \frac{31}{3} \times$ $\frac{8}{8}$
= $\frac{84}{24}$ + $\frac{795}{24}$ + $\frac{2304}{24}$ + $\frac{248}{24}$
=$\frac{3431}{24}$
=142$\frac{23}{24}$ oz
