Answer
$\frac{1}{32}$ in
Work Step by Step
Diameter of 6011 welding rods = $\frac{1}{8}$ in.
Diameter of super strength 100 rods = $\frac{3}{32}$ in.
Difference of the diameters = $\frac{1}{8}$ in. - $\frac{3}{32}$ in
=$\frac{1}{8}$x$\frac{4}{4}$ - $\frac{3}{32}$
= $\frac{4}{32}$ - $\frac{3}{32}$
= $\frac{1}{32}$ in
