Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Section 8.4 - Rationalizing the Denominator - Exercise Set - Page 600: 29

Answer

$\frac{5\sqrt3}{2}$

Work Step by Step

$\frac{15}{\sqrt{12}}$ Simplify by factoring out perfect squares. $\frac{15}{\sqrt{(4)(3)}}$ Simplify. $\frac{15}{2\sqrt3}$ Rationalize the denominator. $\frac{15}{2\sqrt3}\times\frac{\sqrt3}{\sqrt3}$ Use product rule for square roots. $\frac{15\sqrt{3}}{6}$ Reduce. Divide the numerator and denominator by greatest common factor of 3. $\frac{5\sqrt3}{2}$
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