Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Section 8.4 - Rationalizing the Denominator - Exercise Set - Page 600: 26

Answer

$\frac{\sqrt{2}}{6}$

Work Step by Step

$\frac{1}{\sqrt{18}}$ Simplify by factoring out perfect squares. $\frac{1}{\sqrt{(9)(2)}}$ Simplify. $\frac{1}{3\sqrt2}$ Rationalize the denominator. $\frac{1}{3\sqrt2}\times\frac{\sqrt2}{\sqrt2}$ Use product rule for square roots. $\frac{\sqrt{2}}{6}$
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