Answer
$7\sqrt{6} +6$
Work Step by Step
RECALL:
(i) For non-negative real numbers $a$ and $b$,
$\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}$
(ii) For all real numbers $a, b,$ and $c$,
$a(b+c) = ab+ac$
Use rule (ii) above to obtain:
$=\sqrt{6 } \cdot 7 +\sqrt{6} \cdot \sqrt{6}
\\=7\sqrt{6}+\sqrt{6} \cdot \sqrt{6}$
Use rule (i) above to obtain:
$=7\sqrt{6} +\sqrt{36}
=7\sqrt{6} +\sqrt{6^2}
=7\sqrt{6} +6$
