Answer
$\sqrt{2} + \sqrt{11}$ (cannot be simplified further)
Work Step by Step
A radical involving a square is already in lowest terms when the radicand has no perfect square factor.
Note that the radicands of $\sqrt{2}$ amd $\sqrt{11}$ are prime numbers, which means that they have no factors other than themselves.
Therefore, the given expression is already in lowest terms.
