Answer
$10y^{11}\sqrt{6y}$
Work Step by Step
Getting the perfect factors and then extracting its root, the simplified form of the given expression, $
\sqrt{600y^{23}}
,$ is
\begin{array}{l}\require{cancel}
\sqrt{100y^{22}\cdot 6y}
\\\\=
\sqrt{(10y^{11})^2\cdot 6y}
\\\\=
10y^{11}\sqrt{6y}
.\end{array}
Note that variables are assumed to represent positive real numbers.
