Answer
$4-12x^5+9x^{10}$
Work Step by Step
Using $(a\pm b)^2=a^2\pm2ab+b^2$ or the square of a binomial, the square of the given expression, $
(2-3x^5)^2
,$ is
\begin{array}{l}\require{cancel}
(2)^2-2(2)(3x^5)+(3x^5)^2
\\\\=
4-12x^5+9x^{10}
.\end{array}