Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Review Exercises - Page 751: 68

Answer

$x=\frac{-3}{2}$

Work Step by Step

We know that if $a\gt0,a\ne1$, then $a^b=a^c\longrightarrow b=c$ $\frac{1}{27}=3^{-3}, 9^x=(3^2)^x=3^{2x}$ Thus here: $2x=-3\\x=\frac{-3}{2}$
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