Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Review Exercises - Page 751: 56

Answer

$\log_b{21}$

Work Step by Step

The product rule for logarithms says that $\log_b{MN}=\log_bM+\log_bN$ i.e. the logarithm of a product is the sum of the logarithms. Hence here: $\log_b7+\log_b3=\log_b{(3\cdot7)}=\log_b{21}$
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