Answer
$(-\infty,-1)\cup(-1,\infty)$.
Work Step by Step
Also $\log_a b$ to be defined, $a\ne1,a\gt0$ and $b\gt0$.
Hence here $(x+1)^2\gt0\\x\ne-1$
Thus the domain is $(-\infty,-1)\cup(-1,\infty)$.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 9 - Review Exercises - Page 750: 45
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