Answer
$-2$
Work Step by Step
Note that $\dfrac{1}{25}=\dfrac{1}{5^2} = 5^{-2}$.
Write $\dfrac{1}{25}$ as $5^{-3}$ to obtain:
$=\log_5{(5^{-3})}$
Use the rule "$\log_b{(b^x)}=x$" to obtain:
$\log_5{(5^{-2})} = -2$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 9 - Review Exercises - Page 750: 31
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