Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 571: 131

Answer

$\sqrt{-9}+\sqrt{-16}=3i+4i=7i$.

Work Step by Step

The given expression is $=\sqrt{-9}+\sqrt{-16}$ Rewrite as shown below. $=\sqrt{9}\cdot \sqrt {-1}+\sqrt{16}\cdot \sqrt {-1}$ $=\sqrt{3^2}\cdot \sqrt {-1}+\sqrt{4^2}\cdot \sqrt {-1}$ Use $ \sqrt {-1}=i$ $=3i+4i$ Add both terms. $=7i$.
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