Answer
$(21+i)$ volts.
Work Step by Step
$I=(2-3i)$ amperes and $R=(3+5i) ohms$.
The formula is
$\Rightarrow E=IR$.
Substitute the values.
$\Rightarrow E=(2-3i)(3+5i)$.
Use the FOIL method.
$\Rightarrow E=6+10i-9i-15i^2$.
Use $i^2=-1$.
$\Rightarrow E=6+10i-9i+15$.
Add like terms.
$\Rightarrow E=21+i$.
Hence, the value of $E$ is $(21+i)$ volts.
