Answer
$0$
Work Step by Step
$(-2+\sqrt{6})^{2}=(\sqrt{6}-2)^{2}=(\sqrt{6})^{2}-2\cdot\sqrt{6}\cdot 2+2^{2}$
$=6+4-4\sqrt{6}=10-4\sqrt{6}$
$f(-2+\sqrt{6})=10-4\sqrt{6}+4(-2+\sqrt{6})-2$=
$= 10-4\sqrt{6}-8+4\sqrt{6}-2$
... add like terms
$=0$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.5 - Multiplying with More Than One Term and Rationalizing Denominators - Exercise Set - Page 551: 114
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