Answer
$13\sqrt2$
Work Step by Step
$\sqrt{72}+\sqrt{32}+\sqrt{18}=\sqrt{36}\sqrt2+\sqrt{16}\sqrt2+\sqrt{9}\sqrt2=6\sqrt2+4\sqrt2+3\sqrt2=13\sqrt2$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.4 - Adding, Subtracting, and Dividing Radical Expressions - Exercise Set - Page 541: 100
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