Answer
$=\sqrt{\frac{72x^3}{2x}} =\sqrt{36x^2}=6x$.
Work Step by Step
The given expression is
$\frac{\sqrt {72x^3}}{\sqrt {2x}}$
Divide the radicals and retain the common index.
$=\sqrt{\frac{72x^3}{2x}}$
Divide factors in the radicand. Subtract exponents on common bases.
$=\sqrt{36x^2}$
Simplify.
$=\sqrt{6^2x^2}$
$=6x$.
