Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.4 - Adding, Subtracting, and Dividing Radical Expressions - Concept and Vocabulary Check - Page 538: 3

Answer

$\sqrt[3] {27\cdot 2}+\sqrt[3] {8\cdot 2}=3\sqrt[3] { 2}+2\sqrt[3] { 2}=5\sqrt[3] { 2}$.

Work Step by Step

The given expression is $\sqrt[3] {54}+\sqrt[3] {16}$ Factor: $\sqrt[3] {27\cdot 2}+\sqrt[3] {8\cdot 2}$ Use $\sqrt[3] {a^3}=a$ $3\sqrt[3] { 2}+2\sqrt[3] { 2}$ Simplify. $5\sqrt[3] { 2}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.