Answer
$\dfrac{1}{64}$
Work Step by Step
$16^{-\frac{3}{2}}=\dfrac{1}{16^{\frac{3}{2}}}=\dfrac{1}{\sqrt{16}^3}=\dfrac{1}{4^3}=\dfrac{1}{64}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.2 - Rational Exponents - Concept and Vocabulary Check - Page 521: 7
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
