Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.6 - Rational Equations - Exercise Set - Page 464: 58

Answer

$1$ learning trial The point the graph: $(1,0.5)$.

Work Step by Step

Replace $f(x)$ with $0.5$ in the function's formula. $\Rightarrow 0.5=\frac{0.9x-0.4}{0.9x+0.1}$ Multiply both sides by $(0.9x+0.1)$ to clear denominators. $\Rightarrow (0.9x+0.1)0.5=(0.9x+0.1)\cdot \frac{0.9x-0.4}{0.9x+0.1}$ Simplify. $\Rightarrow 0.45x+0.05=0.9x-0.4$ Add $-0.45x+0.4$ to both sides. $\Rightarrow 0.45x+0.05-0.45x+0.4=0.9x-0.4-0.45x+0.4$ Simplify. $\Rightarrow 0.45=0.45x$ Divide both sides by $0.45$. $\Rightarrow \frac{0.45}{0.45}=\frac{0.45x}{0.45}$ Simplify. $\Rightarrow 1=x$ Hence, the learning trials are $1$. The point the graph is $(1,f(1))=(1,0.5)$.
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