Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.6 - Rational Equations - Exercise Set - Page 464: 57

Answer

$11$ learning trials The point the graph: $(11,0.95)$

Work Step by Step

Replace $f(x)$ with $0.95$ in the function's formula. $\Rightarrow 0.95=\frac{0.9x-0.4}{0.9x+0.1}$ Multiply both sides by $(0.9x+0.1)$ to clear denominators. $\Rightarrow (0.9x+0.1)0.95=(0.9x+0.1)\cdot \frac{0.9x-0.4}{0.9x+0.1}$ Simplify. $\Rightarrow 0.855x+0.095=0.9x-0.4$ Add $-0.855x+0.4$ to both sides. $\Rightarrow 0.855x+0.095-0.855x+0.4=0.9x-0.4-0.855x+0.4$ Simplify. $\Rightarrow 0.495=0.045x$ Divide both sides by $0.045$. $\Rightarrow \frac{0.495}{0.045}=\frac{0.045x}{0.045}$ Simplify. $\Rightarrow 11=x$ Hence, the learning trials are $11$. The point the graph is $(11,f(11))=(11,0.95)$.
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