Answer
$x^2-9$.
Work Step by Step
$x^2-9=(x+3)(x-3)$, thus the LCD of $x+3$ and $x-3$ is $x^2-9$.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Section 6.5 - Synthetic Division and the Remainder Theorem - Exercise Set - Page 455: 59
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