Answer
See below.
Work Step by Step
$2x(x+3)+6(x-3)=28\\2x^2+6x+6x-18=-28\\2x^2+12x+10=0\\x^2+6x+5=0\\x^2+x+5x+5=0\\x(x+1)+5(x+1)=0\\(x+1)(x+5)=0$
Thus $x=-1$ or $x=5$.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Section 6.5 - Synthetic Division and the Remainder Theorem - Exercise Set - Page 455: 55
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