Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set - Page 371: 4

Answer

$(2x-3)(2x+3)$

Work Step by Step

RECALL: A difference of two squares can be factored using the formula: $a^2-b^2=(a-b)(a+b)$ The given binomial can be written as: $=(2x)^2-3^2$ This binomial is a difference of two squares. Factor the given difference of two squares using the formula above with $a=2x$ and $b=3$ to obtain: $=(2x-3)(2x+3)$
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