Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set - Page 371: 12

Answer

$(5x^2-3y^3)(5x^2+3y^3)$

Work Step by Step

RECALL: A difference of two squares can be factored using the formula: $a^2-b^2=(a-b)(a+b)$ The given binomial can be written as: $=(5x^2)^2-(3y^3)^2$ This binomial is a difference of two squares. Factor the given difference of two squares using the formula above with $a=5x^2$ and $b=3y^3$ to obtain: $=(5x^2-3y^3)(5x^2+3y^3)$
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