Answer
$\frac{-1}{9}\leq x$
Work Step by Step
$g(x)\leq f(x)\\\frac{3}{8}(16-8x)-7\leq\frac{3}{5}(10x-15)+9\\6-3x-7\leq6x-9+9\\-3x-1\leq6x\\-1\leq9x\\\frac{-1}{9}\leq x$
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