Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Mid-Chapter Check Point - Page 286: 17

Answer

$\left\{ -2,7\right \}$.

Work Step by Step

The given equation is $\Rightarrow 3- \left | 2x-5\right |=-6$ Subtract $3$ from both sides. $\Rightarrow 3- \left | 2x-5\right |-3=-6-3$ Simplify. $\Rightarrow - \left | 2x-5\right |=-9$ Multiply by $-1$ on both sides. $\Rightarrow -1(- \left | 2x-5\right |)=-1(-9)$ Simplify. $\Rightarrow \left | 2x-5\right |=9$ Rewrite the equation without absolute value bars. $\Rightarrow 2x-5=9$ or $2x-5=-9$ Solve both equations separately. First equation. $\Rightarrow 2x-5=9$ Add $5$ to both sides. $\Rightarrow 2x-5+5=9+5$ Add like terms. $\Rightarrow 2x=14$ Divide both sides by $2$. $\Rightarrow \frac{2x}{2}=\frac{14}{2}$ Simplify. $\Rightarrow x=7$ Second equation. $\Rightarrow 2x-5=-9$ Add $5$ to both sides. $\Rightarrow 2x-5+5=-9+5$ Add like terms. $\Rightarrow 2x=-4$ Divide both sides by $2$. $\Rightarrow \frac{2x}{2}=\frac{-4}{2}$ Simplify. $\Rightarrow x=-2$ Hence, the solution set is $\left\{ -2,7\right \}$.
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