Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Cumulative Review Exercises - Page 311: 5

Answer

$\Rightarrow (f-g)(x)=2x^2+x+2$ $\Rightarrow (f-g)(2)=12$.

Work Step by Step

The given functions are $f(x)=3x^2-4x+1$ and $g(x)=x^2-5x-1$ By using the definition of the difference $f-g$. $\Rightarrow (f-g)(x)=f(x)-g(x)$ Substitute the given functions. $\Rightarrow (f-g)(x)=3x^2-4x+1-(x^2-5x-1)$ Remove the parentheses and change the sign of each term in the second set of parentheses. $\Rightarrow (f-g)(x)=3x^2-4x+1-x^2+5x+1$ Add like terms. $\Rightarrow (f-g)(x)=2x^2+x+2$ Replace $x$ with $2$ in the above function. $\Rightarrow (f-g)(2)=2(2)^2+(2)+2$ Clear the parentheses. $\Rightarrow (f-g)(2)=8+2+2$ Add like terms. $\Rightarrow (f-g)(2)=12$
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