Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Cumulative Review Exercises - Page 311: 4

Answer

$f(-3)=22$. $f(2a)=4a^2-6a+4$.

Work Step by Step

The given function is $f(x)=x^2-3x+4$ To find $f(-3)$, replace $x$ with $-3$. $\Rightarrow f(-3)=(-3)^2-3(-3)+4$ Clear the parentheses. $\Rightarrow f(-3)=9+9+4$ Add like terms. $\Rightarrow f(-3)=22$. To find $f(2a)$, replace $x$ with $2a$. $\Rightarrow f(2a)=(2a)^2-3(2a)+4$ Clear the parentheses. $\Rightarrow f(2a)=4a^2-6a+4$.
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