Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.3 - Systems of Linear Equations in Three Variables - Exercise Set - Page 216: 27

Answer

The numbers are $7,4$ and $5$.

Work Step by Step

Let the three numbers be $a,b$ and $c$. From the question we have $\Rightarrow a+b+c=16$ ...... (1) $\Rightarrow 2a+3b+4c=46$ ...... (2) $\Rightarrow 5a-b=31$ ...... (3) Multiply the first equation by $4$. $\Rightarrow 4(a+b+c)=4(16)$ $\Rightarrow 4a+4b+4c=64$ ...... (4) Subtract equation (2) from equation (4). $\Rightarrow 4a+4b+4c-(2a+3b+4c)=64-46$ Simplify. $\Rightarrow 4a+4b+4c-2a-3b-4c=64-46$ Add like terms. $\Rightarrow 2a+b= 18$ ...... (5) Add equation (3) and (5). $\Rightarrow 5a-b+2a+b=31+18$ Simplify. $\Rightarrow 7a=49$ Divide both sides by $7$. $\Rightarrow a=7$. Substitute the value of $a$ into equation (5). $\Rightarrow 2(7)+b= 18$ Simplify. $\Rightarrow 14+b= 18$ Subtract $14$ from both sides. $\Rightarrow 14+b-14= 18-14$ Simplify. $\Rightarrow b= 4$ Substitute the values of $a$ and $b$ into equation (1). $\Rightarrow 7+4+c=16$ Add like terms. $\Rightarrow 11+c=16$ Subtract $11$ from both sides. $\Rightarrow 11+c-11=16-11$ Simplify. $\Rightarrow c=5$
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