Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.3 - Systems of Linear Equations in Three Variables - Exercise Set - Page 216: 18

Answer

No solution.

Work Step by Step

The given equations are $\Rightarrow 3x+4y+5z=8$ ......(1) $\Rightarrow x-2y+3z=-6$ ......(2) $\Rightarrow 2x-4y+6z=8$ ......(3) Multiply equation (2) by $2$. $\Rightarrow 2x-4y+6z=-12$ ......(4) Now add equation (1) and (4). $\Rightarrow 3x+4y+5z+2x-4y+6z=8-12$ Add like terms. $\Rightarrow 5x+11z=-4$ ...... (5) Add equation (1) and (3). $\Rightarrow 3x+4y+5z+2x-4y+6z=8+8$ Add like terms $\Rightarrow 5x+11z=16$ ......(6) Subtract equation (5) from equation (6). $\Rightarrow 5x+11z-(5x+11z)=16-(-4)$ Simplify. $\Rightarrow 5x+11z-5x-11z=16+4$ $\Rightarrow 0=20$ The above statement is false. Hence, there is no solution.
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