Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.3 - Systems of Linear Equations in Three Variables - Exercise Set - Page 215: 7

Answer

$(2,-1,1)$

Work Step by Step

To solve the given problem we will have to plug the simplest equation into the other equation and then solve for the other variable. $9x+3z=21$ and $x-2z=0$ This gives $x=2$ Now, $2-2z=0$ or, $z=1$ Also, $2+2y-1=-1$ or, $2y+1=-1$ or, $2y=-2$ or, $y=-1$ Hence, the desired result is: $(2,-1,1)$
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