Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.3 - Systems of Linear Equations in Three Variables - Exercise Set - Page 215: 5

Answer

$(2,3,3)$

Work Step by Step

To solve the given problem we will have to plug the simplest equation into the other equation and then solve for the other variable. $x+y+2z=11$ and $-x-y-3z=-14$ This gives, $z=3$ Now, $-x-7y=-23$ or, $-x-21=-23$ or, $x=2$ Also, $x+y+2z=11$ $2+y+6=11$ or, $y=3$ Hence, the desired result is $(2,3,3)$
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