Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.2 - Problem Solving and Business Applications Using Systems of Equations - Exercise Set - Page 207: 59

Answer

$(6,300)$.

Work Step by Step

The given revenue function is $\Rightarrow R(x)=50x$ Let $R(x)=y$ $\Rightarrow y=50x$ Let $x=0$. $\Rightarrow y=50(0)$ $\Rightarrow y=0$ One point is $A=(0,0)$ Let $x=1$. $\Rightarrow y=50(1)$ $\Rightarrow y=50$ Second point is $B=(1,50)$ Now draw a straight line containing both points. The given cost function is $\Rightarrow C(x)=20x+180$ Let $C(x)=y$ $\Rightarrow y=20x+180$ Let $x=0$. $\Rightarrow y=20(0)+180$ $\Rightarrow y=180$ One point is $C=(0,180)$ Let $x=1$. $\Rightarrow y=20(1)+180$ $\Rightarrow y=20+180$ $\Rightarrow y=200$ Second point is $D=(1,200)$ Now draw a straight line containing both points. The intersection point of both lines is the break even point. In the below graph the break even point is $(6,300)$.
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