Answer
Hence, $15 \; ml$ of sodium-iodine is needed.
Work Step by Step
$ 50 $ milliliters of a $ 30\% $ sodium-iodine solution.
$30 \% = 0.30$
In the mathematical expression we can write
The number of milliliters of Sodium iodine needed is
$ = 50 \times0.30$
$ =15 $.
