Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.1 - Systems of Linear Equations in Two Variables - Exercise Set - Page 193: 97

Answer

a) Sold = 150 and supplied =300 b) Sold = 250 and supplied =250

Work Step by Step

a) Since, we have $N= -5P+750$ and $N= 2.5P$ Thus, when $P=120$ Then $N= -5(120)+750=150$ and $N= 2.5(120)=300$ Therefore, Sold = 150 and supplied =300 b) Since, we have $N= -5P+750$ and $N= 2.5P$ Thus, when $-5P+750= 2.5P$ or, $P=\dfrac{750}{7.5}=100$ Now, when $P=100$ then $N= -5(100)+750=250$ and $N= 2.5(100)=250$ Therefore, Sold = 250 and supplied =250 Hence, a) Sold = 150 and supplied =300 b) Sold = 250 and supplied =250
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.