Answer
$\{(x,y)|y=4x-5\}$ or $\{(x,y)|8x-2y=10\}$.
Work Step by Step
The given system of equations are
$\Rightarrow y=4x-5$ ......(1)
$\Rightarrow 8x-2y=10$ ......(2)
Isolate $y$ in equation (2).
$\Rightarrow 8x-2y=10$
Add $-8x$ to both sides.
$\Rightarrow 8x-2y-8x=10-8x$
Simplify.
$\Rightarrow -2y=-8x+10$
Divide both sides by $-2$.
$\Rightarrow \frac{-2y}{-2}=\frac{-8x+10}{-2}$
Simplify.
$\Rightarrow y=4x-5$ ...... (3)
Equation (1) and (3) are same.
Hence, the system has infinitely many solutions.
The solution set is
$\{(x,y)|y=4x-5\}$ or $\{(x,y)|8x-2y=10\}$.
