Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.5 - The Point-Slope Form of the Equation of a Line - Exercise Set - Page 167: 92

Answer

$A=-\frac{3}{7}$.

Work Step by Step

The given equation of the line is $\Rightarrow Ax+y=2$ Isolate $y$. $y=-Ax+2$ This is in the standard slope-intercept form. Slope $m_1=-A$. The slope of the line passing through the points $(1,-3)$ and $(-2,4)$ is: $\Rightarrow m_2=\frac{change \; in \; y}{change \; in \; x}$ $\Rightarrow m_2=\frac{4-(-3)}{-2-1}$ $\Rightarrow m_2=\frac{4+3}{-3}$ $\Rightarrow m_2=-\frac{7}{3}$ Two lines are perpendicular if their slopes are negative reciprocal to each other. Hence, we have: $\Rightarrow m_1=−\frac{1}{m_2}$ Substitute all values. $\Rightarrow -A=−\frac{1}{-\frac{7}{3}}$ Simplify. $\Rightarrow -A=\frac{3}{7}$ $\Rightarrow A=-\frac{3}{7}$.
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