Answer
$a_7=8019$
Work Step by Step
Let us consider the sequence $a_n=a_13^{n-1}$
Now, $n=7$ and $a_1=11$
Thus, $a_7=a_13^{7-1}$
or, $a_7=a_13^{6}$
or, $a_7=(11)(729)=8019$
Hence, $a_7=8019$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 11 - Section 11.2 - Arithmetic Sequences - Exercise Set - Page 842: 95
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