Answer
$x=1005$
Work Step by Step
As we know: $logm-log n=log\dfrac{m}{n}$
Thus, $log(\dfrac{x^2-25}{x+5})=3$
or, $log(\dfrac{x^2-25}{x+5})=3$
or, $log(x-5)=3$
or, $x-5=10^3 \implies x-5=1000$
or, $x=1005$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 11 - Section 11.2 - Arithmetic Sequences - Exercise Set - Page 842: 90
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