Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.2 - Arithmetic Sequences - Exercise Set - Page 840: 63

Answer

$1400$

Work Step by Step

Our aim is to determine a formula for the general term of the arithmetic sequence $a_n$. Such as: $a_n=a_1+(n-1)d$ we have For company A:$a_{10}=24,000+9 (1600)=38400$ and For company B: $b_{10}=28000+9 (1000)=37000$ Thus, we can see that Company A can pay more than Company B, that is $a_{10} \gt b_{10}$ or, $d=2$ Hence, $a_{10} -b_{10}=38400-37000=1400$
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